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During Its Manufacture, a Product Is Subjected to Four Different (x1)\left( x _ { 1 } \right)

Question 2

Multiple Choice

During its manufacture, a product is subjected to four different tests in sequential order. An efficiency expert claims that the fourth (and last) test is unnecessary since its results can be predicted based on the first three tests. To test this claim, multiple regression will be used to model Test4 score (y) , as a function of Test1 score (x1) \left( x _ { 1 } \right) , Test 2 score (x2) \left( x _ { 2 } \right) , and Test3 score ( x3) \left. x _ { 3 } \right) ) . [Note: All test scores range from 200 to 800 , with higher scores indicative of a higher quality product.] Consider the model:
E(y) =β1+β1x1+β2x2+β3x3E ( y ) = \beta _ { 1 } + \beta _ { 1 } x _ { 1 } + \beta _ { 2 } x _ { 2 } + \beta _ { 3 } x _ { 3 }
The first-order model was fit to the data for each of 12 units sampled from the production line. The results are summarized in the printout.
 SOURCE  DF  SS  MS  F VALUE  PROB > F  MODEL 31514175047218.16.0075 ERROR 8222312779 TOTAL 12173648\begin{array}{lrrrrr}\hline & & & & & \\\text { SOURCE } & \text { DF } & \text { SS } & \text { MS } & \text { F VALUE } & \text { PROB }>\text { F } \\\text { MODEL } & 3 & 151417 & 50472 & 18.16 & .0075 \\\text { ERROR } & 8 & 22231 & 2779 & & \\\text { TOTAL } & 12 & 173648 & & &\end{array}

 ROOT MSE 52.72 R-SQUARE 0.872 DEP MEAN 645.8 ADJ R-SQ 0.824\begin{array}{llll}\text { ROOT MSE } & 52.72 & \text { R-SQUARE } & 0.872 \\\text { DEP MEAN } & 645.8 & \text { ADJ R-SQ } & 0.824\end{array}

 PARAMETER  STANDARD  T FOR 0:  VARIABLE  ESTIMATE  ERROR  PARAMETER =0 PROB >T INTERCEPT 11.9880.500.150.885 X1(TEST1)  0.27450.11112.470.039 X2(TEST2)  0.37620.09863.820.005 X3(TEST3)  0.32650.08084.040.004\begin{array}{lrrrr} & \text { PARAMETER } & \text { STANDARD } & \text { T FOR 0: } & \\\text { VARIABLE } & \text { ESTIMATE } & \text { ERROR } & \text { PARAMETER }=0 & \text { PROB }>|\mathrm{T}| \\\text { INTERCEPT } & 11.98 & 80.50 & 0.15 & 0.885 \\\text { X1(TEST1) } & 0.2745 & 0.1111 & 2.47 & 0.039 \\\text { X2(TEST2) } & 0.3762 & 0.0986 & 3.82 & 0.005 \\\text { X3(TEST3) } & 0.3265 & 0.0808 & 4.04 & 0.004 \\\hline\end{array}

Compute a 95%95 \% confidence interval for β3\beta _ { 3 } .


A) . 33±10533 \pm 105
B) .33±4.04.33 \pm 4.04
C) .33±.08.33 \pm .08
D) .33±.19.33 \pm .19

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