Solve.
-$\sqrt [ 3 ] { 4 x + 5 } - 4 = 0$
A) 12
B) $\frac { 59 } { 4 }$
C) $\frac { 11 } { 4 }$
D) 16

Name: Solve. -$\sqrt [ 3 ] { 4 x + 5 } - 4 = 0$ A) 12 B) $\frac { 59 } { 4 }$ C) $\frac { 11 } { 4 }$ D) 16
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Question

Quizplus · Accepted Answer

To solve the equation $\sqrt [ 3 ] { 4 x + 5 } - 4 = 0$, add 4 to both sides to get $\sqrt [ 3 ] { 4 x + 5 } = 4$. Cube both sides to get $4x + 5 = 64$. Subtract 5 from both sides to get $4x = 59$. Divide by 4 to get $x = \frac{59}{4}$.

Solve - 4x+53−4=0\sqrt [ 3 ] { 4 x + 5 } - 4 = 034x+5​−4=0

Solve
- $\sqrt [ 3 ] { 4 x + 5 } - 4 = 0$