Solve.
-$\sqrt { 1 + 8 \sqrt { x } } = 1 + \sqrt { x }$
A) 0,100
B) 0,36
C) $0 , \frac { 4 } { 7 }$
D) 0,64

Name: Solve. -$\sqrt { 1 + 8 \sqrt { x } } = 1 + \sqrt { x }$ A) 0,100 B) 0,36 C) $0 , \frac { 4 } { 7 }$ D) 0,64
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Question

Quizplus · Accepted Answer

Squaring both sides of the equation $\sqrt { 1 + 8 \sqrt { x } } = 1 + \sqrt { x }$ gives $1 + 8\sqrt{x} = 1 + 2\sqrt{x} + x$. Simplifying, we get $6\sqrt{x} = x$, which leads to $36x = x^2$. Solving $x^2 - 36x = 0$ gives $x(x - 36) = 0$, so $x = 0$ or $x = 36$.

Solve - 1+8x=1+x\sqrt { 1 + 8 \sqrt { x } } = 1 + \sqrt { x }1+8x​​=1+x​

Solve
- $\sqrt { 1 + 8 \sqrt { x } } = 1 + \sqrt { x }$