Solve.
-$\sqrt { 6 x + 3 } = \sqrt { 4 x + 3 } - 1$
A) $- \frac { 1 } { 2 } , \frac { 11 } { 2 }$
B) $\varnothing$
C) $- \frac { 11 } { 2 } , 3$
D) $- \frac { 1 } { 2 }$

Name: Solve. -$\sqrt { 6 x + 3 } = \sqrt { 4 x + 3 } - 1$ A) $- \frac { 1 } { 2 } , \frac { 11 } { 2 }$ B) $\varnothing$ C) $- \frac { 11 } { 2 } , 3$ D) $- \frac { 1 } { 2 }$
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Question

Quizplus · Accepted Answer

Squaring both sides and solving the resulting equation gives $x = -\frac{1}{2}$. Checking for extraneous solutions confirms it is valid.

Solve - 6x+3=4x+3−1\sqrt { 6 x + 3 } = \sqrt { 4 x + 3 } - 16x+3​=4x+3​−1

Solve
- $\sqrt { 6 x + 3 } = \sqrt { 4 x + 3 } - 1$