Solve.
-$\sqrt { \mathrm { x } ^ { 2 } + 1 } = 8$
A) $63 , - 63$
B) $\sqrt { 7 }$
C) $3 \sqrt { 7 } , - 3 \sqrt { 7 }$
D) 7

Name: Solve. -$\sqrt { \mathrm { x } ^ { 2 } + 1 } = 8$ A) $63 , - 63$ B) $\sqrt { 7 }$ C) $3 \sqrt { 7 } , - 3 \sqrt { 7 }$ D) 7
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Question

Quizplus · Accepted Answer

Squaring both sides of the equation gives $x^2 + 1 = 64$, which simplifies to $x^2 = 63$. Therefore, $x = \pm \sqrt{63}$.

Solve - x2+1=8\sqrt { \mathrm { x } ^ { 2 } + 1 } = 8x2+1​=8

Solve
- $\sqrt { \mathrm { x } ^ { 2 } + 1 } = 8$