Factor.
-$14 x ^ { 2 } - 49 x - 28$
A) $( 2 x - 1 ) ( 7 x + 28 )$
B) $( 14 x - 7 ) ( x + 4 )$
C) $7 ( 2 x + 1 ) ( x - 4 )$
D) $7 ( 2 x - 1 ) ( x + 4 )$

Question

Quizplus · Accepted Answer

The correct factorization is found by first factoring out the greatest common factor (GCF), which is 7, resulting in $7(2x^2 - 7x - 4)$. Then, by finding factors of -8 (the product of 2 and -4) that add up to -7 (the middle term), which are -8 and 1, we can further factor the quadratic to get $7(2x^2 - 8x + x - 4)$, simplifying to $7((2x^2 - 8x) + (x - 4))$, and then $7(2x(x - 4) + 1(x - 4))$, finally resulting in $7(2x + 1)(x - 4)$.

Factor - 14x2−49x−2814 x ^ { 2 } - 49 x - 2814x2−49x−28

Factor
- $14 x ^ { 2 } - 49 x - 28$