Factor.
-$10 y ^ { 2 } + 45 y - 25$
A) $( 2 y - 1 ) ( 5 y + 25 )$
B) $( 10 y - 5 ) ( y + 5 )$
C) $5 ( 2 y - 1 ) ( y + 5 )$
D) $5 ( 2 y + 1 ) ( y - 5 )$

Question

Quizplus · Accepted Answer

The correct factorization is found by first factoring out the greatest common factor, which is 5, resulting in $5(2y^2 + 9y - 5)$. Then, by finding factors of -10 (from $2 \times -5$) that add up to 9 (the middle term's coefficient), which are 10 and -1, the expression can be further factored into $5(2y^2 + 10y - y - 5)$, simplifying to $5((2y^2 + 10y) - (y + 5))$, and then $5(2y(y + 5) - 1(y + 5))$, finally resulting in $5(2y - 1)(y + 5)$.

Factor - 10y2+45y−2510 y ^ { 2 } + 45 y - 2510y2+45y−25

Factor
- $10 y ^ { 2 } + 45 y - 25$