The Following MINITAB Output Display Presents the Results of a Hypothesis

The following MINITAB output display presents the results of a hypothesis test for the difference $\mu _ { 1 } - \mu _ { 2 }$ between two population means.
$\begin{array}{lrcrc}\hline{\text { Two-sample T for X1 vs X2 }} & \\\text { A } & 12 & \text { Mean } & \text { StDev } & \text { SE Mean } \\\text { B } & 8 & 46.021 & 22.014 & 6.355 \\\text { B } & 40.649 & 27.337 & 9.665\end{array}$

Difference $= m u ( X 1 ) - m u ( X 2 )$
Estimate for difference: $25.372$
$95 \%$ CI for difference: $( 2.700,48.044 )$
T-Test of difference $= 0 ($ vs not $= ) : \quad$ T-Value $= 2.193456$
$\mathrm { P } - \mathrm { Value } = 0.04706 \mathrm { DF } = 13$
What is the alternate hypothesis?

A) $\mu _ { 1 } < \mu _ { 2 }$
B) $\mu _ { 1 } > \mu _ { 2 }$
C) $\mu _ { 1 } \neq \mu _ { 2 }$
D) $\mu _ { 1 } = \mu _ { 2 }$