The Following MINITAB Output Display Presents the Results of a Hypothesis

The following MINITAB output display presents the results of a hypothesis test for the difference $\mu _ { 1 } - \mu _ { 2 }$ between two population means.
$\begin{array}{rrrrc}\hline{\text { Two-sample T for X1 vs X2 }} \\& \text { N } & \text { Mean } & \text { StDev } & \text { SE Mean } \\\text { A } & 12 & 66.021 & 22.014 & 6.355 \\\text { B } & 8 & 40.649 & 27.337 & 9.665\end{array}$

Difference $= \operatorname { mu } ( \mathrm { X } 1 ) - \mathrm { mu } ( \mathrm { X } 2 )$
Estimate for difference: $25.372$
$95 \%$ CI for difference: $( 2.700,48.044 )$

$\mathrm { T }$ -Test of difference $= 0 ($ vs not $= ) : \quad \mathrm { T } - \mathrm { Value } = 2.193456$
P-Value $= 0.04706 \mathrm { DF } = 13$

Can you reject $H _ { 0 }$ rejected at the $\alpha = 0.10$ level?

A) No
B) Yes