$$\begin{array}{l}
\text { The following distribution is $\underline{\text { not }}$ a probability distribution because }\
\begin{array} { l | c c c c c }
\boldsymbol { X } & - 2 & - 1 & 0 & 1 & 2 \
\hline \boldsymbol { P } ( \boldsymbol { X } ) & 0.16 & 0.15 & 0.42 & 0.13 & 0.31
\end{array}
\end{array}$$
A) the probability values are not increasing.
B) the probability values are not discrete.
C) the values of the variable are negative.
D) the probability values do not add to 1.

Question

$$\begin{array}{l}
\text { The following distribution is $\underline{\text { not }}$  a probability distribution because }\
\begin{array} { l | c c c c c } 
\boldsymbol { X } & - 2 & - 1 & 0 & 1 & 2 \
\hline \boldsymbol { P } ( \boldsymbol { X } ) & 0.16 & 0.15 & 0.42 & 0.13 & 0.31
\end{array}
\end{array}$$
A) the probability values are not increasing.
B) the probability values are not discrete.
C) the values of the variable are negative.
D) the probability values do not add to 1.

Quizplus · Accepted Answer

The sum of the probability values exceeds 1 (0.16 + 0.15 + 0.42 + 0.13 + 0.31 = 1.17), which violates the fundamental property of a probability distribution where the sum of all probabilities must equal 1.

A) the Probability Values Are Not Increasing