$$\begin{array}{l}
\text { Find the mean of the distribution shown below. }\
\begin{array} { l | c c c }
\boldsymbol { X } & 2 & 3 & 4 \
\hline \boldsymbol { P } ( \boldsymbol { X } ) & 0.36 & 0.32 & 0.32
\end{array}
\end{array}$$
A) 1.60
B) 2.96
C) 2.92
D) 2.56

Question

$$\begin{array}{l}
\text { Find the mean of the distribution shown below. }\
\begin{array} { l | c c c } 
\boldsymbol { X } & 2 & 3 & 4 \
\hline \boldsymbol { P } ( \boldsymbol { X } ) & 0.36 & 0.32 & 0.32
\end{array}
\end{array}$$
A) 1.60
B) 2.96
C) 2.92
D) 2.56

Quizplus · Accepted Answer

The mean of a distribution is calculated by summing the products of each value and its probability. Here, it's $2(0.36) + 3(0.32) + 4(0.32) = 0.72 + 0.96 + 1.28 = 2.96$.

A) 160 B) 2

A) 160
B) 2