$$\begin{array}{l}
\text { Give the mean of the following probability distribution. }\
\begin{array} { l | c c c c }
\boldsymbol { X } & 2 & 3 & 4 & 5 \
\hline \boldsymbol { P } ( \boldsymbol { X } ) & 0.50 & 0.25 & 0.15 & 0.10
\end{array}
\end{array}$$
A) 1.28
B) 0.25
C) 2.85
D) 3.50

Question

$$\begin{array}{l}
\text { Give the mean of the following probability distribution. }\
\begin{array} { l | c c c c } 
\boldsymbol { X } & 2 & 3 & 4 & 5 \
\hline \boldsymbol { P } ( \boldsymbol { X } ) & 0.50 & 0.25 & 0.15 & 0.10
\end{array}
\end{array}$$
A) 1.28
B) 0.25
C) 2.85
D) 3.50

Quizplus · Accepted Answer

The mean of a probability distribution is found by multiplying each outcome by its probability and summing these products: $2(0.50) + 3(0.25) + 4(0.15) + 5(0.10) = 1 + 0.75 + 0.6 + 0.5 = 2.85$.

A) 128 B) 0

A) 128
B) 0