A 385-g tile hangs from one end of a string that goes over a pulley with a moment of inertia of $0.0125 \mathrm {~kg} \cdot \mathrm { m } ^ { 2 }$ and a radius of 15.0 cm. A mass of 710 g hangs from the other end of the string. When the tiles are released, the larger one accelerates downward while the lighter one accelerates upward. The pulley has no friction in its axle and turns without the string slipping. What is the tension in the string on the side of the 710-g tile?
A) 3.68 N
B) 6.87 N
C) 9.77 N
D) 5.59 N
E) 4.41 N

Question

A 385-g tile hangs from one end of a string that goes over a pulley with a moment of inertia of $0.0125 \mathrm {~kg} \cdot \mathrm { m } ^ { 2 }$ and a radius of  15.0 cm. A mass of  710 g hangs from the other end of the string. When the tiles are released, the larger one accelerates downward while the lighter one accelerates upward. The pulley has no friction in its axle and turns without the string slipping. What is the tension in the string on the side of the  710-g tile?
A)  3.68 N
B)  6.87 N
C)  9.77 N
D)  5.59 N
E)  4.41 N

Quizplus · Accepted Answer

The tension in the string on the side of the 710-g tile can be found by considering the forces and torques acting on the system. The difference in weight between the two masses causes the system to accelerate, and the pulley's moment of inertia must be taken into account to find the net acceleration and tension. The correct tension value is calculated by applying Newton's second law and the rotational dynamics equations, considering the system's constraints and properties.

A 385-G Tile Hangs from One End of a String 0.0125 kg⋅m20.0125 \mathrm {~kg} \cdot \mathrm { m } ^ { 2 }0.0125 kg⋅m2

A 385-G Tile Hangs from One End of a String $0.0125 \mathrm {~kg} \cdot \mathrm { m } ^ { 2 }$