A ballerina spins initially at 1.5 rev/s when her arms are extended. She then draws in her arms to her body and her moment of inertia becomes $0.88 \mathrm {~kg} \cdot \mathrm { m } ^ { 2 }$ and her angular speec increases to 4.0 rev/s. What was her initial moment of inertia?

Question

A ballerina spins initially at  1.5 rev/s  when her arms are extended. She then draws in her arms to her body and her moment of inertia becomes $0.88 \mathrm {~kg} \cdot \mathrm { m } ^ { 2 }$ and her angular speec increases to  4.0 rev/s. What was her initial moment of inertia?

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The Answer of A ballerina spins initially at  1.5 rev/s  when her arms are extended. She then draws in her arms to her body and her moment of inertia becomes $0.88 \mathrm {~kg} \cdot \mathrm { m } ^ { 2 }$ and her angular speec increases to  4.0 rev/s. What was her initial moment of inertia?

A Ballerina Spins Initially at 1 0.88 kg⋅m20.88 \mathrm {~kg} \cdot \mathrm { m } ^ { 2 }0.88 kg⋅m2

A Ballerina Spins Initially at 1 $0.88 \mathrm {~kg} \cdot \mathrm { m } ^ { 2 }$