A golf club exerts an average horizontal force of 1000 N on a 0.045-kg golf ball that is initially at rest on the tee. The club is in contact with the ball for 1.8 ms. What is the speed of the golf ball just
As it leaves the tee?
A) 40 m/s
B) 45 m/s
C) 30 m/s
D) 35 m/s
E) 50 m/s

Question

Quizplus · Accepted Answer

Impulse = change in momentumImpulse = F * tChange in momentum = m * vF * t = m * vv = F * t / mv = 1000 N * 1.8 ms / 0.045 kgv = 40 m/s

A Golf Club Exerts an Average Horizontal Force of 1000