A steady horizontal force lasting for 2.1 s gives a 1.25 kg object an acceleration of $3.2 \mathrm {~m} / \mathrm { s } ^ { 2 }$ on a frictionless table. What impulse does this force give to the object?
A) $2.6 \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$
B) $26 \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$
C) $8.4 \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$
D) $11 \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$

Question

A steady horizontal force lasting for  2.1 s gives a  1.25 kg object an acceleration of $3.2 \mathrm {~m} / \mathrm { s } ^ { 2 }$ on a frictionless table. What impulse does this force give to the object?
A) $2.6 \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$
B) $26 \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$
C) $8.4 \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$
D) $11 \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$

Quizplus · Accepted Answer

Impulse is calculated as the product of force and time. The force can be found using $ F = ma $, where $ m = 1.25 \, \text{kg} $ and $ a = 3.2 \, \text{m/s}^2 $. Thus, $ F = 1.25 \times 3.2 = 4 \, \text{N} $. The impulse is then $ 4 \, \text{N} \times 2.1 \, \text{s} = 8.4 \, \text{kg} \cdot \text{m/s} $.

A Steady Horizontal Force Lasting for 2 3.2 m/s23.2 \mathrm {~m} / \mathrm { s } ^ { 2 }3.2 m/s2

A Steady Horizontal Force Lasting for 2 $3.2 \mathrm {~m} / \mathrm { s } ^ { 2 }$