A very light ideal spring stretches by 21.0 cm when it is used to hang a 135-N object. What is the weight of a piece of electronic equipment that would stretch the spring by 44.9 cm if you hung the
Equipment using the spring?
A) 289 N
B) 176 N
C) 405 N
D) 63 N

Question

Quizplus · Accepted Answer

The spring constant k can be calculated using Hooke's Law: F = kx. For the 135-N object, k = 135 N / 0.21 m. For the electronic equipment, using the same spring constant, F = k * 0.449 m. Solving gives F = 289 N.

A Very Light Ideal Spring Stretches by 21