A person throws a ball horizontally from the top of a building that is 24.0 m above the ground level. The ball lands 100 m down range from the base of the building. What was the initial velocity
Of the ball? Neglect air resistance and use g = 9.81 m/s².
A) 45.2 m/s
B) 19.6 m/s
C) 9.80 m/s
D) 202 m/s
E) 94.4°

Question

Quizplus · Accepted Answer

The time to fall 24.0 m is found using the equation $ t = \sqrt{\frac{2h}{g}} $. Substituting $ h = 24.0 $ m and $ g = 9.81 $ m/s² gives $ t \approx 2.21 $ s. The horizontal velocity is then $ v = \frac{d}{t} = \frac{100}{2.21} \approx 45.2 $ m/s.

A Person Throws a Ball Horizontally from the Top of a Building