An object is thrown upwards with a speed of 16 m/s. How long does it take it to reach a height of 7.0 m on the way up? Neglect air resistance.
A) 0.52 s
B) 1.2 s
C) 3.1 s
D) 4.2 s
E) 2.4 s

Question

Quizplus · Accepted Answer

To find the time it takes for the object to reach a height of 7.0 m, we can use the equation of motion under constant acceleration (gravity in this case, $g = 9.8 \, \text{m/s}^2$), which is $s = ut + \frac{1}{2}at^2$, where $s$ is the displacement (7.0 m in this case), $u$ is the initial velocity (16 m/s), $a$ is the acceleration (due to gravity, which is -9.8 m/s$^2$ since it's acting opposite to the direction of motion), and $t$ is the time. Rearranging the equation to solve for $t$ and substituting the given values, we find that $t \approx 0.52 \, \text{s}$.

An Object Is Thrown Upwards with a Speed of 16