The inductor in a radio receiver carries a current of amplitude $0.200 \mathrm {~A}$ when an ac voltage of amplitude $2.40 \mathrm {~V}$ is across it at a frequency of $1400 \mathrm {~Hz}$. What is the value of the inductance?
A) $1.97 \mathrm { mH }$
B) $4.42 \mathrm { mH }$
C) $1.36 \mathrm { mH }$
D) $9.20 \mathrm { mH }$
E) $1.43 \mathrm { mH }$

Question

Quizplus · Accepted Answer

The inductive reactance $X_L$ is given by $X_L = \frac{V}{I} = \frac{2.40}{0.200} = 12 \, \Omega$. The inductive reactance is also given by $X_L = 2\pi f L$. Solving for $L$, we have $L = \frac{X_L}{2\pi f} = \frac{12}{2\pi \times 1400} \approx 1.36 \, \mathrm{mH}$.

The Inductor in a Radio Receiver Carries a Current of Amplitude