At what frequency will a $20.0 - \mathrm { mH }$ inductor have an inductive reactance of $100 \Omega$ ?
A) $796 \mathrm {~Hz}$
B) $225 \mathrm {~Hz}$
C) $655 \mathrm {~Hz}$
D) $457 \mathrm {~Hz}$
E) None of the other answers is correct.

Question

Quizplus · Accepted Answer

The inductive reactance $X_L$ is given by $X_L = 2\pi fL$, where $f$ is the frequency in hertz (Hz), $L$ is the inductance in henries (H), and $X_L$ is the inductive reactance in ohms ($\Omega$). Rearranging this formula to solve for $f$, we get $f = \frac{X_L}{2\pi L}$. Substituting $X_L = 100 \Omega$ and $L = 20.0 \times 10^{-3} \, \mathrm{H}$ (or $0.020 \, \mathrm{H}$), we find $f = \frac{100}{2\pi \times 0.020} \approx 796 \, \mathrm{Hz}$.

At What Frequency Will A 20.0−mH20.0 - \mathrm { mH }20.0−mH

At What Frequency Will A $20.0 - \mathrm { mH }$