What charge accumulates on the plates of a $2.0 - \mu \mathrm { F }$ air-filled capacitor when it is charged until the potential difference across its plates is $100 \mathrm {~V}$ ?

Question

Quizplus · Accepted Answer

The charge $Q$ on a capacitor is given by the formula $Q = CV$, where $C$ is the capacitance in farads and $V$ is the potential difference in volts. Substituting $C = 2.0 \mu F = 2.0 \times 10^{-6} F$ and $V = 100 V$, we get $Q = 2.0 \times 10^{-6} F \times 100 V = 200 \times 10^{-6} C = 200 \mu C$.

What Charge Accumulates on the Plates of A 2.0−μF2.0 - \mu \mathrm { F }2.0−μF

What Charge Accumulates on the Plates of A $2.0 - \mu \mathrm { F }$