A uniform electric field, with a magnitude of $500 \mathrm {~V} / \mathrm { m }$, is points in the $+ x$ direction. If the potential at $x = 5.0 \mathrm {~m}$ is $2500 \mathrm {~V}$, what is the potential at $x = 2.0 \mathrm {~m}$ ?

Question

Quizplus · Accepted Answer

The potential difference $ V $ between two points in a uniform electric field is given by $ V = E \cdot d $, where $ E $ is the electric field and $ d $ is the distance. The potential at $ x = 2.0 \mathrm{~m} $ is $ 2500 \mathrm{~V} - 500 \mathrm{~V/m} \times (5.0 \mathrm{~m} - 2.0 \mathrm{~m}) = 2500 \mathrm{~V} - 1500 \mathrm{~V} = 1000 \mathrm{~V} $ or $ 1.0 \mathrm{~kV} $.

A Uniform Electric Field, with a Magnitude Of 500 V/m500 \mathrm {~V} / \mathrm { m }500 V/m

A Uniform Electric Field, with a Magnitude Of $500 \mathrm {~V} / \mathrm { m }$