A battery maintains the electrical potential difference of $6.0 - \mathrm { V }$ between two large parallel metal plates separated by $1.0 \mathrm {~mm}$. What is the strength of the electric field between the plates?

Question

Quizplus · Accepted Answer

The electric field strength $E$ between parallel plates is given by $E = \frac{V}{d}$, where $V$ is the potential difference and $d$ is the separation. Here, $E = \frac{6.0 \, \mathrm{V}}{1.0 \times 10^{-3} \, \mathrm{m}} = 6000 \, \mathrm{V/m}$.

A Battery Maintains the Electrical Potential Difference Of 6.0−V6.0 - \mathrm { V }6.0−V

A Battery Maintains the Electrical Potential Difference Of $6.0 - \mathrm { V }$