A $15 - \mu \mathrm { F }$ capacitor is connected to a 50 - $\mathrm { V }$ battery and becomes fully charged. The battery is removed and a slab of dielectric, having a dielectric constant of $5.0$, is inserted between the plates and completely fills the space between them.
(a) What is the capacitance of the capacitor after the slab is inserted?
(b) What is the potential difference across the capacitor with the dielectric inserted.

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The Answer of A $15 - \mu \mathrm { F }$ capacitor is connected to a 50 - $\mathrm { V }$ battery and becomes fully charged. The battery is removed and a slab of dielectric, having a dielectric constant of $5.0$, is inserted between the plates and completely fills the space between them.
(a) What is the capacitance of the capacitor after the slab is inserted?
(b) What is the potential difference across the capacitor with the dielectric inserted.

A 15−μF15 - \mu \mathrm { F }15−μF Capacitor Is Connected to a 50 -

A $15 - \mu \mathrm { F }$ Capacitor Is Connected to a 50 -