A gas expands from an initial volume of $30.0 \mathrm {~L}$ to a final volume of $65.0 \mathrm {~L}$ at a constant pressure of $110 \mathrm { kPa }$. How much work is done by the gas during this expansion?
A) $10.4 \mathrm { MJ }$
B) $3.85 \mathrm { MJ }$
C) $3.85 \mathrm {~kJ}$
D) $10.4 \mathrm {~kJ}$
E) $3850 \mathrm {~kJ}$

Question

Quizplus · Accepted Answer

The work done by the gas during expansion at constant pressure can be calculated using the formula $W = P \Delta V$, where $P$ is the pressure and $\Delta V$ is the change in volume. Here, $P = 110 \mathrm { kPa } = 110 \times 10^3 \mathrm { Pa }$ and $\Delta V = 65.0 \mathrm { L} - 30.0 \mathrm { L} = 35.0 \mathrm { L} = 35.0 \times 10^{-3} \mathrm { m^3}$ (since $1 \mathrm { L } = 10^{-3} \mathrm { m^3}$). Thus, $W = 110 \times 10^3 \mathrm { Pa } \times 35.0 \times 10^{-3} \mathrm { m^3} = 3850 \mathrm { J } = 3.85 \mathrm { kJ }$.

A Gas Expands from an Initial Volume Of 30.0 L30.0 \mathrm {~L}30.0 L

A Gas Expands from an Initial Volume Of $30.0 \mathrm {~L}$