During an isothermal process, $5.0 \mathrm {~J}$ of heat is removed from an ideal gas. What is the change in internal (thermal) energy of the gas?
A) $10 \mathrm {~J}$
B) $2.5 \mathrm {~J}$
C) $5.0 \mathrm {~J}$
D) $0 \mathrm {~J}$

Question

Quizplus · Accepted Answer

For an ideal gas undergoing an isothermal process, the temperature remains constant. According to the first law of thermodynamics, the change in internal energy is equal to the heat added to the system minus the work done by the system. Since the temperature is constant, the internal energy of an ideal gas does not change, making the change in internal energy 0 J, regardless of the heat removed or work done.

During an Isothermal Process 5.0 J5.0 \mathrm {~J}5.0 J Of Heat Is Removed from an Ideal Gas

During an Isothermal Process $5.0 \mathrm {~J}$ Of Heat Is Removed from an Ideal Gas