If you add 700 kJ of heat to 700 g of water originally at $70.0 ^ { \circ } \mathrm { C }$ how much water is left in the container? The latent heat of vaporization of water is $22.6 \times 10 ^ { 5 } \mathrm {~J} / \mathrm { kg }$ and its specific heat capacity is $4186 \mathrm {~J} / \mathrm { kg } \cdot \mathrm { K } .$

Question

If you add  700 kJ of heat to  700 g of water originally at $70.0 ^ { \circ } \mathrm { C }$ how much water is left in the  container? The latent heat of vaporization of water is $22.6 \times 10 ^ { 5 } \mathrm {~J} / \mathrm { kg }$ and its specific heat capacity is $4186 \mathrm {~J} / \mathrm { kg } \cdot \mathrm { K } .$

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The Answer of If you add  700 kJ of heat to  700 g of water originally at $70.0 ^ { \circ } \mathrm { C }$ how much water is left in the  container? The latent heat of vaporization of water is $22.6 \times 10 ^ { 5 } \mathrm {~J} / \mathrm { kg }$ and its specific heat capacity is $4186 \mathrm {~J} / \mathrm { kg } \cdot \mathrm { K } .$

If You Add 700 KJ of Heat to 70.0∘C70.0 ^ { \circ } \mathrm { C }70.0∘C

If You Add 700 KJ of Heat to $70.0 ^ { \circ } \mathrm { C }$