A person tries to heat up her bath water by adding 5.0 L of water at $80 ^ { \circ } \mathrm { C }$ to 60 L of water at $30 ^ { \circ } \mathrm { C }$ What is the final temperature of the bath water?

Question

A person tries to heat up her bath water by adding  5.0 L of water at $80 ^ { \circ } \mathrm { C }$ to  60 L of water at $30 ^ { \circ } \mathrm { C }$ What is the final temperature of the bath water?

Quizplus · Accepted Answer

The final temperature can be calculated using the formula for mixing two liquids: $T_f = \frac{(m_1 \cdot T_1) + (m_2 \cdot T_2)}{m_1 + m_2}$. Substituting the given values, $T_f = \frac{(5 \cdot 80) + (60 \cdot 30)}{5 + 60} = 34 ^ { \circ } \mathrm { C }$.

A Person Tries to Heat Up Her Bath Water by Adding