Find the margin of error for the 95% confidence interval used to estimate the population proportion
-In a survey of 4100 T.V. viewers, 20% said they watch network news programs.
A)0.0122
B)0.00915
C)0.0140
D)0.0160

Question

Quizplus · Accepted Answer

The margin of error (E) for a proportion is calculated using the formula $E = Z \sqrt{\frac{p(1-p)}{n}}$, where $Z$ is the Z-score for the confidence level (1.96 for 95%), $p$ is the sample proportion (0.20), and $n$ is the sample size (4100). Plugging in these values gives $E = 1.96 \sqrt{\frac{0.20(0.80)}{4100}} \approx 0.0122$.

Find the Margin of Error for the 95% Confidence Interval