Find the margin of error for the 95% confidence interval used to estimate the population proportion
-n = 58, x = 28; 95 percent
A)0.353

Question

Find the margin of error for the 95% confidence interval used to estimate the population proportion
-n = 58, x = 28; 95 percent
A)0.353 < p < 0.613
B)0.375 < p < 0.591
C)0.354 < p < 0.612
D)0.374 < p < 0.592

Quizplus · Accepted Answer

The margin of error for a 95% confidence interval is given by:ME = z * sqrt((p(1-p))/n)where z is the z-score corresponding to the desired confidence level, p is the sample proportion, and n is the sample size.For a 95% confidence level, z = 1.96. Substituting the given values into the formula, we get:ME = 1.96 * sqrt((0.28(1-0.28))/58) = 0.129Therefore, the margin of error is 0.129, and the 95% confidence interval is:0.28 +/- 0.129 = (0.354, 0.612)

Find the Margin of Error for the 95% Confidence Interval