Light of wavelength 687 nm is incident on a single slit 0.75 mm wide. At what distance from the slit should a screen be placed if the second dark fringe in the diffraction pattern is to be 1.7 mm from the center of the screen?
A)0.39 m
B)0.47 m
C)0.93 m
D)1.1 m
E)1.9 m

Question

Quizplus · Accepted Answer

The position of the dark fringes in a single-slit diffraction pattern is given by the formula $ y_m = \frac{m \lambda L}{a} $, where $ m $ is the order of the dark fringe, $ \lambda $ is the wavelength, $ L $ is the distance to the screen, and $ a $ is the slit width. For the second dark fringe ($ m = 2 $), solving for $ L $ gives $ L = \frac{y_m a}{m \lambda} $. Substituting the given values: $ y_m = 1.7 \times 10^{-3} $ m, $ a = 0.75 \times 10^{-3} $ m, $ m = 2 $, and $ \lambda = 687 \times 10^{-9} $ m, we find $ L \approx 0.93 $ m.

Light of Wavelength 687 Nm Is Incident on a Single