A 200-m radio telescope is used to investigate sources emitting a 21-cm wavelength. The minimum angular separation resolvable for this system is
A)0.073°.
B)0.03°.
C)0.0013°.
D)0.154°.
E)0.0026°.

Question

Quizplus · Accepted Answer

The minimum angular separation resolvable for a radio telescope is given by the Rayleigh criterion:$$	heta = 1.22 \frac{\lambda}{D}$$where $	heta$ is the angular separation, $\lambda$ is the wavelength, and $D$ is the diameter of the telescope.Plugging in the given values, we get:$$	heta = 1.22 \frac{0.21 	ext{ m}}{200 	ext{ m}} = 0.0013^\circ$$Therefore, the correct answer is C) 0.0013°.

A 200-M Radio Telescope Is Used to Investigate Sources Emitting