An ac generator has 80 rectangular loops on its armature. Each loop is 12 cm long and 8 cm wide. The armature rotates at 1200 rpm about an axis parallel to the long side. If the loop rotates in a uniform magnetic field of 0.30 T, which is perpendicular to the axis of rotation, what will be the maximum output voltage of this generator?

Question

Quizplus · Accepted Answer

The maximum output voltage of an ac generator is given by:V = NBAωwhere N is the number of loops, B is the magnetic field strength, A is the area of each loop, and ω is the angular velocity.In this problem, we have:N = 80B = 0.30 TA = (0.12 m)(0.08 m) = 9.6 × 10^-3 m^2ω = (1200 rpm)(2π rad/rev)(1 min/60 s) = 40π rad/sPlugging these values into the equation, we get:V = (80)(0.30 T)(9.6 × 10^-3 m^2)(40π rad/s) = 29.0 VTherefore, the maximum output voltage of this generator is 29 V.

An Ac Generator Has 80 Rectangular Loops on Its Armature