You are designing a generator with a maximum emf 8.0 V. If the generator coil has 200 turns and a cross-sectional area of 0.030 m², what would be the frequency of the generator in a magnetic field of 0.030 T?

Question

Quizplus · Accepted Answer

The correct answer is A because the frequency of the generator is given by the equation f = emf / (2πNAω), where emf is the maximum emf, N is the number of turns in the coil, A is the cross-sectional area of the coil, and ω is the angular frequency of the generator. In this case, emf = 8.0 V, N = 200 turns, A = 0.030 m2, and ω = 2πf. Substituting these values into the equation, we get f = 8.0 V / (2π * 200 turns * 0.030 m2 * 2πf) = 7.1 Hz.

You Are Designing a Generator with a Maximum Emf 8