A parallel-plate capacitor has a plate separation of 5.0 cm. If the potential difference between the plates is 2000 V, with the top plate at the higher potential, what is the electric field between the plates?

Question

Quizplus · Accepted Answer

The electric field (E) between the plates of a parallel-plate capacitor is given by the formula E = V/d, where V is the potential difference and d is the separation between the plates. Here, V = 2000 V and d = 0.05 m. Thus, E = 2000 / 0.05 = 40000 N/C. Since the top plate is at a higher potential, the electric field direction is downward.

A Parallel-Plate Capacitor Has a Plate Separation of 5