The potential difference between the plates of a parallel plate capacitor is 35 V and the electric field between the plates has a strength of 750 V/m. If the plate area is 4.0 × 10^-2 m², what is the capacitance of this capacitor?

Question

Quizplus · Accepted Answer

The capacitance of a parallel plate capacitor is given by:

C = εA/d

where ε is the permittivity of the dielectric material between the plates, A is the area of each plate, and d is the distance between the plates.

We are given the potential difference V = 35 V and the electric field strength E = 750 V/m. We can use these values to find the distance between the plates:

V = Ed
35 = (750)(d)
d = 0.0467 m

Now we can calculate the capacitance:

C = (8.85×10^-12)(4.0×10^-2) / 0.0467
C = 7.6×10^-12 F

Therefore, the answer is B.

The Potential Difference Between the Plates of a Parallel Plate