The potential difference between the plates of a parallel plate capacitor with the plate separation of 6 cm is 60 V. What is the electric field between the plates of this capacitor?

Question

Quizplus · Accepted Answer

The formula for the electric field between the plates of a parallel plate capacitor is given by:

E = V/d

where E is the electric field, V is the potential difference, and d is the plate separation.

Substituting the given values, we get:

E = 60 V/0.06 m = 1000 V/m

Therefore, the electric field between the plates of this capacitor is 1000 V/m, which corresponds to choice C.

The Potential Difference Between the Plates of a Parallel Plate