A parallel-plate capacitor has a capacitance of 10 mF and is charged with a 20 V power supply. The power supply is then removed and a dielectric of dielectric constant 4 is used to fill the space between the plates. The voltage now across the capacitor is

Question

Quizplus · Accepted Answer

When a dielectric is inserted into a charged capacitor, the voltage across the capacitor decreases by a factor equal to the dielectric constant. Thus, the new voltage is 20 V / 4 = 5 V.

A Parallel-Plate Capacitor Has a Capacitance of 10 MF and Is