Solve the problem.
-The position of a particle moving along a coordinate line is $s = \sqrt { 3 + 6 t }$ with $s$ in meters and $t$ in seconds. Find the particle's acceleration at $t = 1 \mathrm { sec }$.
A) $- \frac { 1 } { 18 } \mathrm {~m} / \mathrm { sec } ^ { 2 }$
B) $1 \mathrm {~m} / \mathrm { sec } ^ { 2 }$
C) $- \frac { 1 } { 3 } \mathrm {~m} / \mathrm { sec } ^ { 2 }$
D) $\frac { 1 } { 3 } \mathrm {~m} / \mathrm { sec } ^ { 2 }$

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The Answer of Solve the problem.
-The position of a particle moving along a coordinate line is $s = \sqrt { 3 + 6 t }$ with $s$ in meters and $t$ in seconds. Find the particle's acceleration at $t = 1 \mathrm { sec }$.
A) $- \frac { 1 } { 18 } \mathrm {~m} / \mathrm { sec } ^ { 2 }$
B) $1 \mathrm {~m} / \mathrm { sec } ^ { 2 }$
C) $- \frac { 1 } { 3 } \mathrm {~m} / \mathrm { sec } ^ { 2 }$
D) $\frac { 1 } { 3 } \mathrm {~m} / \mathrm { sec } ^ { 2 }$

Solve the Problem s=3+6ts = \sqrt { 3 + 6 t }s=3+6t​

Solve the Problem $s = \sqrt { 3 + 6 t }$