Solve the problem.
-What points of the surface $x y - z ^ { 2 } - 6 y + 36 = 0$ are closest to the origin?
A) $( - 2 , - 4 , \pm 2 )$
B) $( - 2,4 , \pm 2 )$
C) $( 2 , - 4 , \pm 2 )$
D) $( 2,4 , \pm 2 )$

Question

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The Answer of Solve the problem.
-What points of the surface $x y - z ^ { 2 } - 6 y + 36 = 0$ are closest to the origin?
A) $( - 2 , - 4 , \pm 2 )$
B) $( - 2,4 , \pm 2 )$
C) $( 2 , - 4 , \pm 2 )$
D) $( 2,4 , \pm 2 )$

Solve the Problem xy−z2−6y+36=0x y - z ^ { 2 } - 6 y + 36 = 0xy−z2−6y+36=0

Solve the Problem $x y - z ^ { 2 } - 6 y + 36 = 0$