Use Summation Notation
-$$\sum _ { i = 1 } ^ { 5 } \frac { ( i + 1 ) ! } { ( i + 2 ) ! }$$
A) $\frac { 153 } { 140 }$
B) $\frac { 547 } { 140 }$
C) $\frac { 39 } { 20 }$
D) $\frac { 81 } { 20 }$ Express the sum using summation notation. Use 1 as the lower limit of summation and i for the index of summation.

Question

Quizplus · Accepted Answer

The expression simplifies to $\sum_{i=1}^{5} \frac{1}{i+2}$, which evaluates to $\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} + \frac{1}{7} = \frac{153}{140}$.

Use Summation Notation - ∑i=15(i+1)!(i+2)!\sum _ { i = 1 } ^ { 5 } \frac { ( i + 1 ) ! } { ( i + 2 ) ! }i=1∑5​(i+2)!(i+1)!​

Use Summation Notation
- $\sum _ { i = 1 } ^ { 5 } \frac { ( i + 1 ) ! } { ( i + 2 ) ! }$