Draw the Lewis structure for the NO₂- ion.What is the total number of electrons shared between nitrogen and the two oxygen atoms?

Question

Quizplus · Accepted Answer

To draw the Lewis structure for the NO₂- ion, we first need to determine the total number of valence electrons. Nitrogen: 5 Oxygen: 6 x 2 = 12 Sulfur: 6 Total: 23 The negative charge of the ion indicates that there is one extra electron, bringing the total to 24. We can then arrange the atoms and electrons as follows: Nitrogen: Oxygen: O-S-O Sulfur: Each atom needs an octet of electrons, except for hydrogen which only needs 2. Starting with the outer atoms, we can share single bonds to satisfy their octets: Nitrogen: Oxygen: O=S-O Sulfur: There are 4 electrons remaining. We can use these to form a double bond between nitrogen and one of the oxygen atoms: Nitrogen: =O Oxygen: O=S-O Sulfur: Finally, we distribute the remaining electrons as lone pairs to each atom, giving us the final Lewis structure: Nitrogen: =O Oxygen: O=S-O Sulfur: Counting the number of electrons shared between nitrogen and the two oxygen atoms, we have a total of 6 (3 from each bond). The answer is D) 6.

Draw the Lewis Structure for the NO2- Ion

Draw the Lewis Structure for the NO₂- Ion