What mass (in grams) of SF₆ should be produced by the following reaction if 7.00 g of sulfur is mixed with 9.00 g of fluorine? S + 3F₂ $\rightarrow$SF₆

Question

Quizplus · Accepted Answer

The limiting reactant is fluorine. The molar mass of F2 is 38 g/mol, so 9.00 g of F2 is 0.237 mol. According to the reaction, 3 mol of F2 produce 1 mol of SF6, so 0.237 mol of F2 produces 0.079 mol of SF6. The molar mass of SF6 is 146 g/mol, so 0.079 mol of SF6 is 11.1 g.

What Mass (In Grams) of SF6 Should Be Produced by the Following

What Mass (In Grams) of SF₆ Should Be Produced by the Following