Find the missing numerator.
-$\frac { 9 x ^ { 2 } } { x - 1 } - \frac { ? } { x - 1 } = 9 x$
A) $9 x$
B) 9
C) $\frac { 9 x ( x + 1 ) } { x - 1 }$
D) $\frac { 9 x } { x - 1 }$

Question

Quizplus · Accepted Answer

To solve for the missing numerator, we need to make the equation true. The equation simplifies to $\frac { 9 x ^ { 2 } - ? } { x - 1 } = 9 x$. For the equation to hold, the numerator must be $9 x ^ { 2 } - 9 x$, because when you distribute $9x$ across $x - 1$, you get $9x^2 - 9x$. Therefore, the missing numerator that makes the equation true is $9x$.

Find the Missing Numerator 9x2x−1−?x−1=9x\frac { 9 x ^ { 2 } } { x - 1 } - \frac { ? } { x - 1 } = 9 xx−19x2​−x−1?​=9x

Find the Missing Numerator $\frac { 9 x ^ { 2 } } { x - 1 } - \frac { ? } { x - 1 } = 9 x$