Find the missing numerator.
-$\frac { x ^ { 2 } - 10 x } { x - 6 } + \frac { ? } { x - 6 } = x - 4$
A) $x - 6$
B) $x + 6$
C) 4
D) 24

Question

Quizplus · Accepted Answer

To find the missing numerator, first combine the fractions on the left side of the equation: $\frac{x^2 - 10x + ?}{x - 6} = x - 4$. For the equation to hold, the numerator must simplify to the same form as the right side when multiplied by $x - 6$. Thus, we need $x^2 - 10x + ? = (x - 6)(x - 4)$. Expanding the right side gives $x^2 - 10x + 24$. Comparing this with the left side, it's clear that the missing term (?) must be 24 to match the constant term on the right side.

Find the Missing Numerator x2−10xx−6+?x−6=x−4\frac { x ^ { 2 } - 10 x } { x - 6 } + \frac { ? } { x - 6 } = x - 4x−6x2−10x​+x−6?​=x−4

Find the Missing Numerator $\frac { x ^ { 2 } - 10 x } { x - 6 } + \frac { ? } { x - 6 } = x - 4$