Add.
-$$\frac { 3 } { 14 x } + \frac { 9 } { 10 x ^ { 2 } }$$
A) $\frac { 12 } { 140 x ^ { 2 } }$
B) $\frac { 15 x + 63 } { 70 x ^ { 2 } }$
C) $\frac { 12 } { 14 x + 10 x ^ { 2 } }$
D) $\frac { 108 } { 70 x ^ { 2 } }$

Question

Quizplus · Accepted Answer

To add the fractions, find a common denominator, which is $70x^2$ (the least common multiple of $14x$ and $10x^2$). Convert each fraction: $\frac{3}{14x} = \frac{3 \cdot 5x}{14x \cdot 5x} = \frac{15x}{70x^2}$ and $\frac{9}{10x^2} = \frac{9 \cdot 7}{10x^2 \cdot 7} = \frac{63}{70x^2}$. Adding these gives $\frac{15x + 63}{70x^2}$.

Add - 314x+910x2\frac { 3 } { 14 x } + \frac { 9 } { 10 x ^ { 2 } }14x3​+10x29​

Add
- $\frac { 3 } { 14 x } + \frac { 9 } { 10 x ^ { 2 } }$