Solve by extracting square roots.
-x $$x ^ { 2 } - \frac { 5 } { 4 } x$$
A) $\frac { 25 } { 64 } ; \left( x - \frac { 5 } { 8 } \right) ^ { 2 }$
B) $0 ; \left( x - \frac { 5 } { 8 } \right) ^ { 2 }$
C) $\frac { 25 } { 16 } ; \left( x - \frac { 5 } { 8 } \right) ^ { 2 }$
D) $\frac { 25 } { 64 } ; \left( x + \frac { 5 } { 8 } \right) ^ { 2 }$

Question

Quizplus · Accepted Answer

We can factor x out of the expression to get:
$x\left(x-\frac{5}{4}\right)$
Then, we can take the square root of both terms:
$x\sqrt{x-\frac{5}{4}}\cdot\sqrt{x-\frac{5}{4}}$
Simplifying, we have:
$x\left(x-\frac{5}{4}\right)=(x)^2-\frac{5}{4}x$
So the answer is $\frac{25}{64}$ and $(x-\frac{5}{8})^2$.

Solve by Extracting Square Roots x2−54xx ^ { 2 } - \frac { 5 } { 4 } xx2−45​x

Solve by Extracting Square Roots $x ^ { 2 } - \frac { 5 } { 4 } x$