The number of typographical errors in a document follows a Poisson distribution with a mean of 2 errors per page. Let X represent the number of errors on 3 pages. Find P(Less than 3).
A) 0.0620
B) 0.0174
C) 0.6767
D) 0.0595

Question

Quizplus · Accepted Answer

The probability of less than 3 errors on 3 pages is the sum of the probabilities of 0, 1, and 2 errors. Using the Poisson distribution with a mean of 2 errors per page, we have:P(X = 0) = e^(-2) * 2^0 / 0! = 0.1353P(X = 1) = e^(-2) * 2^1 / 1! = 0.2707P(X = 2) = e^(-2) * 2^2 / 2! = 0.2707Therefore, P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.1353 + 0.2707 + 0.2707 = 0.6767.

The Number of Typographical Errors in a Document Follows a Poisson