The number of typographical errors in a document follows a Poisson distribution with a mean of 2 errors per page. Let X represent the number of errors on 4 pages. Find P(Greater than 1).
A) 0.5940
B) 0.9862
C) 0.9970
D) 0.9997

Question

Quizplus · Accepted Answer

Since the number of errors on a page follows a Poisson distribution with mean 2, the number of errors on 4 pages follows a Poisson distribution with mean 8. 
P(Greater than 1) = 1 - P(0 or 1 error) = 1 - (P(X=0) + P(X=1))
Using the Poisson distribution formula with lambda=8:
P(X=0) = e^(-8) * 8^0 / 0! = 0.000335
P(X=1) = e^(-8) * 8^1 / 1! = 0.002688
Therefore, P(Greater than 1) = 1 - (0.000335 + 0.002688) = 0.9970.

The Number of Typographical Errors in a Document Follows a Poisson